1.3333m-0.3333m^2=0.5

Solution for 1.3333m-0.3333m^2=0.5 equation:

1.3333m-0.3333m^2=0.5

We move all terms to the left:

1.3333m-0.3333m^2-(0.5)=0

We add all the numbers together, and all the variables

-0.3333m^2+1.3333m-0.5=0

a = -0.3333; b = 1.3333; c = -0.5;
Δ = b2-4ac
Δ = 1.33332-4·(-0.3333)·(-0.5)
Δ = 1.11108889
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.3333)-\sqrt{1.11108889}}{2*-0.3333}=\frac{-1.3333-\sqrt{1.11108889}}{-0.6666}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.3333)+\sqrt{1.11108889}}{2*-0.3333}=\frac{-1.3333+\sqrt{1.11108889}}{-0.6666}
$